4A0-100 Dump, Trustworthy 4A0-100 Practice
4A0-100 Dump, Trustworthy 4A0-100 Practice
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Tags: 4A0-100 Dump, Trustworthy 4A0-100 Practice, 4A0-100 Valid Test Question, Reliable 4A0-100 Exam Blueprint, Braindumps 4A0-100 Pdf
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Alcatel-Lucent 4A0-100 exam is an important certification for networking professionals who want to enhance their skills and knowledge in the field of IP network design. 4A0-100 exam covers a wide range of topics related to scalable IP networks, and candidates are expected to have a good understanding of these topics and be able to apply their knowledge to real-world scenarios. With the right preparation and resources, candidates can pass the 4A0-100 Exam and take their networking career to the next level.
2025 4A0-100: Nokia IP Networksand Services Fundamentals –Trustable Dump
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Alcatel-Lucent Nokia IP Networksand Services Fundamentals Sample Questions (Q134-Q139):
NEW QUESTION # 134
What is the sequence of messages that must be exchanged between a DHCP client and a server for the client to receive an IP address?
- A. Discover, Offer, Request, Acknowledgement
- B. Request, Offer, Discover, Acknowledgement
- C. Discover, Acknowledgement, Request, Offer
- D. Request, Acknowledgement, Discover, Offer
Answer: A
Explanation:
TheDHCP client/server exchangefollows a specific four-step sequence known asDORA:
* Discover- Client broadcasts to find available DHCP servers.
* Offer- DHCP server responds with an IP address offer.
* Request- Client requests the offered IP.
* Acknowledgement- Server confirms the lease.
This ensuresdynamic IP configurationand is used in enterprise and home networks.
Reference:
Nokia IP Fundamentals Guide - DHCP Protocol Operation
RFC 2131 - Dynamic Host Configuration Protocol
NEW QUESTION # 135
Based on the network diagram (click the Exhibit Button). Router 1 installs network D in its routing table following a dynamic routing update from Router 2. Which of the following describes the information that will be installed in the routing table?
- A. 172.16.9.0/24 next-hop 10.10.10.2
- B. 172.16.9.0/24 next-hop 10.10.10.1
- C. 0.0.0.0/32 next-hop 172.16.9.1
- D. 172.16.9.0.24 next-hop 10.10 10 3
Answer: D
NEW QUESTION # 136
Given the associated prefix value, which of the following is a valid host address?
- A. 172.16.224.255/18
- B. 255.255.255.255/32
- C. 192.168.24.59/30
- D. 224.1.2.1/8
Answer: A
NEW QUESTION # 137
How many DS-3 frames can be transported in an OC-3 frame?
- A. 0
- B. 1
- C. 2
- D. 3
Answer: B
NEW QUESTION # 138
How many subnets and host addresses are obtained by subnetting network 201.148.26.0/24 using a /26 subnet mask?
- A. 4 subnets, 62 hosts per subnet
- B. 4 subnets, 64 hosts per subnet
- C. 8 subnets, 30 hosts per subnet
- D. 8 subnets, 32 hosts per subnet
Answer: C
Explanation:
A/26 subnetmeans26 bits for the networkand6 bits for host addressing(32 - 26 = 6):
* 2# = 64 total addresses per subnet
* 64 - 2 =62 usable host addresses per subnet
* /24 to /26 increases subnet bits by 2, so:
* 2² =4 subnetsfrom one /24
* But the question asks aboutusing /26, which means:
* From /24 # each /26 block gives64 IPs
* So you get4 subnets total
* But the options must be interpreted carefully!
#Let's calculate again properly:
* /26 = 64 addresses per subnet (2#)
* Usable hosts per subnet = 64 - 2 = 62
* Number of subnets in /24 when divided by /26 = 2